1，在Hyperledger Fabric 1.0中，所有的Peer节点都是什么节点？
A，应用程序节点
B，排序服务节点
C，CA节点
D，记账节点
答案：D
2，以下哪种节点是Hyperledger Fabric 1.0的证书颁发机构？
A，背书节点
B，排序服务节点
C，CA节点
D，记账节点
答案：C
1 In Hyperledger Fabric 1.0, what are all the Peer nodes?
A, application node
B, sort service node
C, CA node
D, account node
2 answer: D
, which of the following is the certificate issuer for Hyperledger Fabric 1.0?
A, endorsement node
B, sort service node
C, CA node
D, account node
answer: C.
3，在Hyperledger Fabric 1.0中，SignedProposal是封装了Proposal的结构,Proposal由两个部分组成,是哪两部分
A,消息头和消息结构
B,消息签名和消息内容
C,消息头和消息签名
D,消息签名和消息结构
答案：A
3 In Hyperledger Fabric 1.0, SignedProposal is a sealed structure of Proposal consisting of two parts,
A, header and message structure
B, message signature and message content
C, message head and message signature
D, message signature and message structure
answer: A.
4,在Hyperledger Fabric 1.0中,Proposal中的消息头包含两项内容，是哪两项？
A,通道头和签名头
B,消息签名和链码
C,身份证书和签名头
D,通道头和链码
答案：A
4 In Hyperledger Fabric 1.0, the message header in Proposal contains two elements: 之前问题备份： Back up on the question: 2,以下哪个没有包含在比特币区块头中的？ 2, which of the following is not included in the bitcoin block? 答案:D Answer: D 3,比特币采用了什么样的网络架构? What network structure did Bitcoin use? 答案：C Answer: C 4，skycoin的使用的共识算法是什么？ What's the consensus algorithm for 4,skycoin? 1,EOS是基于哪个标准的C++版本开发的？ 1. EOS was developed on the basis of the C++ version of which criteria? 2,EOS的存储是基于以下哪种文件系统? 2 EOS storage is based on the following file system: 3,EOS采用以下哪种共识算法? 3, which of the following consensus algorithms is used by EOS? 1,EOS.IO 软件使得区块准确的每多少时间生成一个？ One, EOS.IO software allows blocks to be generated exactly at each time? 2,在 EOS.IO 软件中，区块通过多少名生产者轮流产生？ 2 In the EOS.IO software, how many producers rotate the blocks? 3,在EOS.IO中如果一个生产者错过了一个区块并且在过去的多少小时内没有生产任何的区块，那么它将被从候选中移除？ 3 If a producer in EOS.IO misses a block and does not produce any block in the last few hours, it will be removed from the candidate? 4,在EOS.IO中通常 DPOS 区块链 100% 会有区块生产者参与。一个交易从广播开始后平均多少秒就可以 99.9% 被认为是确认了？ 4 In the EOS. IO, 100% of the DPOS block chain involves block producers. 99.9% of the average number of seconds from the start of a transaction is considered confirmed? 5,默认情况下，所有的节点将认为当21个生产者中有多少个给出确认后这一区块就是不可逆的了，并且不管长度如何都不会切换到没有这一区块的分叉? 5. By default, all the nodes will consider the block irreversible when confirmed by the 21 producers, and will not, however long it may be, switch to the fork without the block? 6，EOS.IO 软件允许所有的帐户使用一个唯一的人类可读的名称来索引，长度在2到多少个字符之间? 6. The EOS.IO software allows all accounts to be indexed using a unique human readable name in the range of two to how many characters? 1,EOS.IO 软件提供给用户一种找回自己失窃密钥控制权的方式。 一个帐户的所有者可以使用过去多少天任何活跃的拥有者密钥与事先指定的合作者帐户给出的批准来重置自己帐户的密钥? 1 EOS.IO software provides users with a way to recover control of their stolen keys. How many days has an account owner used any active owner's key to replace his account with the approval given by the pre-designated collaborators' account? 2,EOS.IO 软件提供给用户一种找回自己失窃密钥控制权的方式。 一个帐户的所有者可以使用什么方式来重置自己的账户秘钥? 2. The EOS.IO software provides users with a way to recover control of their stolen keys. What can an account owner use to reset his or her account key? 3,EOS.IO 软件将每个区块划分为什么？ Three, the EOS.IO software divides each block? 4,EOS.IO 软件将每个区块中的每个循环划分为什么？ 4. Why does the EOS.IO software divide each cycle in each block? 5,EOS.IO 软件将每个区块中的每个循环中的每个线程划分为什么？ Five, the EOS.IO software divides each of the loops in each block. 6,EOS.IO 软件将每个区块中的每个循环中的每个线程的每个交易划分为什么？ Why does the EOS.IO software divide every line in each block? 7,在EOS.IO中，以下哪类资源不是应用程序消耗的？ 7 In EOS.IO, which of the following types of resources is not consumed by the application? 8，如果一个基于 EOS.IO 的区块链启动了，一个帐户持有所有 token 发行总量的 1%，那么帐号就具有使用多少状态存储空间的能力? 8, if an EOS.IO-based block chain is activated and an account holds 1 per cent of all token issuances, then the account number has the capability to use the state storage space? 9,EOS.IO软件可以配置限定生产者回报的上限从而确保 token 的每年增长比例不会超过多少？ 9, EOS.IO software can be configured to limit producers' returns to ensure that the annual rate of growth of Token does not exceed that of 10,EOS.IO软件冻结账户，需要多少个活跃生产者的投票？ 10, EOS.IO freezes accounts and how many active producers are required to vote? 11,EOS.IO软件更改账户代码，需要多少个活跃生产者的投票？ 11, EOS.IO changes account codes and how many active producers are required to vote? 12，EOS.IO软件与外部区块链进行通信时，区块生产者必须等待直到多少确信一个交易已经被另一个区块链确认为不可逆后才会接收它成为一个有效的输入？ 12, when the EOS.IO software communicates with the external block chain, block producers must wait until they are more or less convinced that a transaction has been recognized as irreversible by another block chain before receiving it as a valid input? 1、以太坊EVM代码操作可以访问三种存储数据的空间，不包括以下哪种？ 1. Three types of data storage space can be accessed with EVM code operations, excluding the following: 2，以太坊使用下面哪个程序来编译智能合约代码？ 2 Ethio uses the following program to compile the smart contract code? 3,以太坊每挖出一个区块奖励矿工5个以太币。在最新的Byzantium版本中，奖励额变为多少个？ In the latest version of Byzantium, how many awards have been awarded? 4,以太坊的挖矿算法并未采用比特币所使用的Sha256，而是在Hashimoto和Dagger基础上建立了自己的什么算法？ 4. Instead of using the Sha256 used in Bitcoin, the Taiku mining algorithm established its own algorithm on the basis of Hashimoto and Dagger? 5,以太坊的挖矿算法Ethash使用了一种什么样的数据结构？ Five, what kind of data structure is Ethash's mining algorithm? 6,以太坊每多少个区块（约125个小时）随机生成一个新的DAG Six, a new DAG 7,以太坊挖矿算法是通过什么软件库实现的? 7. What is the software base through which the Tai Po mine algorithm is implemented? 8,以太坊奖励给被区块矿工收录的叔区块矿工：区块奖励的7/8(即4.375个以太币），Byzantium版本为多少个以太币? 8-Team incentives for uncles who are accepted by block miners: 7/8 block awards (i.e. 4.375 in TT) and how many by Byzantium versions in NT? 9,在未来规划的以太坊哪个版本中，共识机制计划会变更为权益证明（PoS）？ 9 In which version of the future plan, the consensus mechanism plan will be changed as proof of interest? 10,如果交易执行完毕，消耗的gas值小于指定的限制值，则交易执行正常，并将剩余的gas值赋予变量gas_rem ; 在交易完成后，发送者会收到返回的多少价值的以太币？ 10, if the transaction is completed and the gas value consumed is less than the specified limit value, the transaction is performed normally and the remaining gas value is given to the variable gas_rem; After the transaction is completed, the sender will receive the return amount in TT? 11,如果交易执行完毕，消耗的gas值小于指定的限制值，则交易执行正常，并将剩余的gas值赋予变量gas_rem ; 在交易完成后，给矿工的奖励是多少价值的以太币？ 11 If the transaction is completed and the consumed gas value is less than the specified limit value, the transaction is carried out normally and the remaining gas value is assigned to the variable gas_rem; What is the value of the incentive given to miners after the transaction is completed? 12,如果交易执行中，gas消耗殆尽，则所有的执行恢复原样，交易费怎么处理？ 12, if the transaction is under way and the gas is depleted, then all the execution will be restored and the transaction fee will be treated? 13,在以太坊中基本费用是多少？对于任何交易，都将收取这笔费用，用于支付运行椭圆曲线算法、交易存储所占用的磁盘空间和带宽！ 13, what is the basic cost in Etheria? For any transaction, this fee will be charged to cover the disk space and bandwidth used to run the elliptical curve algorithm, transaction storage! 14,在以太坊中的交易数据费用中每笔交易可以包括无限量的“数据”，固定费用为每个零字节多少gas？ 14 Each transaction may include an unlimited amount of “data” in the transaction data cost in Taiku, and the fixed cost is how much gas? 14,在以太坊中的交易数据费用中每笔交易可以包括无限量的“数据”，固定费用为每个非零字节多少gas？ 14 Each transaction may include an unlimited amount of “data” in the transaction data cost in Taiku, and the fixed cost is how much gas? 15,以太坊内存是一个可以无限扩展的数组，然而，每扩展32字节的内存就会消耗多少gas的成本 15, Etheria's RAM is an infinite array, but how much gas costs per 32 bytes of RAM are 16,以太坊的区块哈希是通过什么算法对区块头进行的哈希计算而得？ 16, what algorithm did Hashi calculate for the blockhead? 17,以太坊中采用的序列化格式是什么？ 17, what's the sequenced format used in the courthouse? 18,EVM采用了基于什么的架构。 18, EVM uses a structure based on what. 19,Merkle Patricia树（MPT）是以太坊的主要数据结构。在以太坊每个区块头中，存有三个根值，不包括以下哪个？ 19, Merkle Patricia's tree (MPT) is the main data structure of Tai Ho. There are three root values in each block in Ethio, not including which of the following? 答案：D Answer: D 20，以太坊区块头Nonce，与什么一起用来证明区块已进行了有足够的计算？ 20, Nonce, the head of the Taiwan block, and what is there to prove that the block has been fully calculated? 1,以太坊叔块必须是区块的前2层~前多少层的祖先的直接的子块？ One, the Ethio uncle must be the first two floors of the block - how many layers of the direct ancestor? 新问题： New questions: 7,在以太坊中中，智能合约不能直接发出HTTP请求，为了访问中心化API，可以使用什么服务作为中间人,为从中心化服务智能合约中抓取的数据提供TLSNotary验证 7 In Etheria, smart contracts cannot directly send HTTP requests, and in order to access the centralized API, what service can be used as an intermediary to provide TLSNotary validation of data taken from the centralized services contracts 10，在IPFS中，代表一个实际存储在IPFS中的文件的数据块的是什么？ 10, in IPFS, what is the data block that represents a file actually stored in IPFS? 11，在IPFS中，什么代表完整的文件？ 11, in IPFS, what's a complete document? 12，在IPFS中，什么代表目录？ 12, in IPFS, what's the directory? 13，在IPFS中，什么文件代表其他文件的版本历史中的快照？ 13, in IPFS, what documents represent snapshots in the history of versions of other documents? 14,以太坊有的节点发现协议是以哪种协议为基础？ 14 Which agreement is the basis of the agreement? 15，在以太坊中，当对等节点连接到以太坊网络时，它们首先连接到什么节点，这种节点分享在刚才事先定义的时间里连接到它们的对等节点列表。 15 In Etheria, when peer nodes are connected to Ethernet, they first connect to which nodes, which nodes share the list of peer nodes connected to them at the time just defined. 16,在以太坊中，去中心化的通信协议是哪个？ 16, which is the centralised communication agreement in Etheria? 19,在IPFS中，通过使用什么协议与其他节点进行块(block)交换来实现数据分发？ 19 In IPFS, data distribution is achieved by exchanging blocks (block) with other nodes using what protocols? 再来20： Again 20:
A, channel header and signature header
B, message signature and chain number
1,比特币区块哈希值是多少位字节？
A,16位
B,32位
C,64位
D,128位
答案:B
1, how many bits of Hash in the bitcoin block?
A, 16 bits of B, 32 bits of C, 64 bits of D, 128 bits of B.
A,版本号
B,父区块哈希值
C,Merkle树根值
D,交易记录
A, version
B, parent block Hashi value
A,B2C
B,S2C
C,P2P
D,B2B
A, B2C
B, S2C
C, P2P
D, B2B
A,POS
B,POW
C,Obelisk
D,DPOS
答案：C
A, POS
B, POW
C, Obelisk
D, DPOS
answer: C
A,C++98
B,C++03
C,C++11
D,C++14
答案:D
A, C+98
B, C+03
C, C+11
D, C+14
Answer: D
A,HDFS
B,IPFS
C,EXT3
D,NTFS
答案：B
A, HDFS
B, IPFS
C, EXT3
D, NTFS
answer: B
A,POW
B,DPOS
C,POS
D,PBFT
答案：B
A, Pow
B, DPOS
C, POS
D, PBFT
Answer: B
A,10秒
B,5秒
C,3秒
D,1秒
答案：C
A, 10 seconds
A,11名
B,21名
C,31名
D,41名
答案：B
A, 11
B, 21 br'C, 31 br'D, 41 br's answer: B.
A,2小时
B,10小时
C,12小时
D,24小时
答案：D
A, 2 hours
B, 10 hours
C, 12 hours
A,1.5秒
B,2.5秒
C,3.5秒
D,5.5秒
答案:A
A, 1.5 seconds
B, 2.5 seconds
C, 3.5 seconds
A,12个
B,13个
C,14个
D,15个
答案：D
A, 12 br'B, 13 br'C, 14 br'D, 15 br's answer: D.
A,16
B,32
C,64
D,128
答案：B
A, 16
B, 32
C, 64
D, 128
answer: B
A,15天
B,30天
C,40天
D,50天
答案:B
A, 15 days
B, 30 days
C, 40 days
D, 50 days br answer: B
A,任何账户的批准
B,任何活跃的拥有者密钥与事先指定的合作者帐户给出的批准
C,系统指定账户的批准
D,使用自己的公钥
答案:B
A, approval of any account
B, approval of any active owner's key with approval of the pre-designated partner's account
C, approval of the system with approval of the account
D, and use of his or her public key
A,循环
B,线程
C,交易
D,消息
答案:A
A, loop
B, thread
C, transaction
D, message
answer: A.
A,循环
B,线程
C,交易
D,消息
答案:B
A, loop
B, thread
C, transaction
D, message
, answer: B.
A,循环
B,线程
C,交易
D,消息
答案:C
A, loop
B, thread
C, transaction
D, message
, answer: C.
A,循环
B,线程
C,交易
D,消息
答案:D
A, loop
B, thread
C, deal
D, message
answer: D.
A,带宽和日志存储 (磁盘)
B,计算与计算储备 (中央处理器)
C,状态存储 (内存)
D,显示器
答案：D
A, bandwidth and log storage (disk)
B, calculation and calculation reserve (central processor)
C, state storage (RAM)
D, monitor
answer: D.
A,1%
B,2%
C,5%
D,10%
答案:A
A, 1 per cent
B, 2 per cent
C, 5 per cent >br> D, 10 per cent {br> answer: A
A,5%
B,8%
C,10%
D,12%
答案：A
A, 5%
B, 8%
C, 10%
A,11/21
B,12/21
C,15/21
D,17/21
答案：D
A, 11/21
B, 12/21
C, 15/21
D, 17/21
Answer: D
A,11/21
B,12/21
C,15/21
D,17/21
答案：D
A, 11/21
B, 12/21
C, 15/21
D, 17/21
Answer: D
A,51%
B,70%
C,100%
D,80%
答案：C
A, 51%
B, 70%
C, 100% >br> D, 80%
answer: C
A,堆栈
B,内存
C,合约的长期存储
D,寄存器
答案：D
A, stack
B, memory
C, long-term contract storage
D, sender
answer: D.
A,solc
B,web3.js
C,geth
D,truffle
答案：A
A, solc
B, web3.js
C, geth
D, truffle
answer: A.
A,1个
B,2个
C,3个
D,4个
答案：C
A, 1 br, 2 br, 2 br, 3 br, D, 4 br.
A,DAG
B,SHA64
C,ethhash
D,ASIC
答案：C
A, DAG
B, SHA64
C,ethash
D, ASIC
answer: C
A,BTREE
B,TireTree
C,Dictionary
D,DAG
答案：D
A, BTREE
B, FireTree
C, Dictionary
D, DAG
answer: D.
A,10000个
B,20000个
C,30000个
D,40000个
答案：C
A,OPENGL
B,SDL
C,GTK2
D,OPENCL
答案：D
A, OPNGL
B, SDL
C, GTK2
D, OPNCL
answer: D
A,2个
B,2.5个
C,2.625个
D,2.75个
答案：C
A, 2 br'B, 2.5 br'C, 2.625 br'D, 2.75 br' answer: C
A,Serenity
B,Metropolis
C,Homestead
D,Frontier
答案：A
A, service
B, Metropolis
C, Homestead
D, Frontier
answer: A.
A,gas_rem * gasprice
B,gas_rem + gasprice
C,gas_rem - gasprice
D,gas_rem / gasprice
答案：A
A, gas_rem*gasprice
B,gas_rem +gaspricice
C,gas_rem -gaspricice
D,gas_rem/gasprice
answer: A.
A,（startgas + gas_rem）* gasprice
B,（startgas - gas_rem）* gasprice
C,（startgas * gas_rem）* gasprice
D,（startgas / gas_rem）* gasprice
答案：B
A, (startgas + gas_rem)
C, (startgas_remb>D, (startgas_rem)*gasprice
answer: B
A，将 startgas * gasprice 价值的以太币支付给矿工
B, 退回交易费
C，将 1/2 * startgas * gasprice 价值的以太币支付给矿工
D, 交易费用丢失
答案：A
A, pay the miner
B in tatgas * gasprice, return the transaction fee
C, pay the miner
A,22000gas
B,21000gas
C,2000gas
D,19000gas
答案：B
A,22000gas
B,21000gas
C,2000gas
D19,000gas
answer: B
A,2gas
B,4gas
C,6gas
D,8gas
答案:B
A, 2gas
B, 4gas
C, 6gas
D, 8gas
answer: B
A,16gas
B,32gas
C,64gas
D,68gas
答案:D
A, 16gas
B, 32gas
C, 64gas
D, 68gas
answer: D.
A,0.1gas
B,1gas
C,2gas
D,3gas
答案：B
A, 0.1 gas
B, 1gas
C, 2gas
D, 3gas
answer: B
A,Keccak256
B,Keccak128
C,SHA-256
D,SHA-128
答案：A
A, Keccak256
B, Keccak128
C, SHA-256
D, SHA-128
answer: A.
A,JSON
B,XML
C,YML
D,RLP
答案：D
A, JSON
B, XML
C, YML
D, RLP
Answer: D
A,基于栈的架构
B,基于寄存器的架构
C,基于树的架构
D,基于图的架构
答案：A
A, a structure based on a warehouse
B, a structure based on a register
C, a tree based structure
D, a structure based on a graph
A,State Root(账户状态根哈希)
B,Transactions Root(区块交易根哈希)
C,Receipts Root(接收账户根哈希)
D,Uncle Hash(叔区块哈希)
A, State Root (account state)
B, Transactions Root (block trade
C, Receipts Root (received account
D, Uncle Hash)
A,Timestamp
B,Difficulty
C,Mix Hash
D,Extra Data
答案：C
A,5
B,6
C,7
D,8
答案：C
1，以太坊货币单位中，单位babbage等于多少wei ?
A,1e3 wei
B,1e6 wei
C,1e9 wei
D,1e12 wei
答案：A
2，以太坊货币单位中，单位lovelace等于多少wei ?
A,1e3 wei
B,1e6 wei
C,1e9 wei
D,1e12 wei
答案：B
3，以太坊货币单位中，单位shannon等于多少wei ?
A,1e3 wei
B,1e6 wei
C,1e9 wei
D,1e12 wei
答案：C
4，以太坊货币单位中，单位szabo等于多少wei ?
A,1e3 wei
B,1e6 wei
C,1e9 wei
D,1e12 wei
答案：D
5，以太坊货币单位中，单位finney等于多少wei ?
A,1e3 wei
B,1e6 wei
C,1e9 wei
D,1e15 wei
答案：D
6，以太坊货币单位中，单位ether等于多少wei ?
A,1e3 wei
B,1e6 wei
C,1e9 wei
D,1e18 wei
答案：D
1, in verbage, how much wei? > B, 1e6 wei
B, 1e6 wei
C, 1e9 wei
D, 1e12 wei
Answer: A
2, in verb monetary unit, how much wei?
B, 1e6 wei
, 1wei
A,Oraclize
B,Truffle
C,Geth
D,Miner
答案：A
8，当在IPFS中存储一个文件时，它被分成很多小于多少KB的数据块（chunk）？
A,128
B,256
C,512
D,1024
答案：B
9，下列哪种不是IPFS文件类型？
A,blob
B,list
C,tree
D,chunk
答案：D
A, Oracle
B, Truffle
C, Geth
D, Minar
answer: A
8; when a document is stored in an IPFS, it is divided into data blocks smaller than KB (chunk)?
A, 128
B, 256
C, 512
D, 1024
answer: B
9; which of the following are not IPFS types?
A,blob
B,list
C,tree
D,commit
答案：A
A, blob
B,list
C,tree
D,committee
Answer: A.
A,blob
B,list
C,tree
D,commit
答案：B
A, blob
B,list
C,tree
D,committee
Answer: B.
A,blob
B,list
C,tree
D,commit
答案：C
A, blob
B,list
C,tree
D,committee
answer: C.
A,blob
B,list
C,tree
D,commit
答案：D
A, blob
B,list
C,tree
D,committee
Answer: D.
A，Kadelima协议
B，Whisper协议
C，Swarm协议
D，ghost协议
答案：A
A, Kadelima
B, Whisper
C, Swarmo
D, Gost
answer: A.
A，挖矿节点
B，Bootstrap节点
C，中央服务器
D，其他对等节点
答案:B
A, dig nodes
B, Bootstrap nodes
C, central server
D, other peer nodes
answer: B
A，Kadelima
B，Whisper
C，Swarm
D，ghost
答案：B
17,在以太坊中，以下哪个是去中心化的存储平台？
A，Kadelima
B，Whisper
C，Swarm
D，ghost
答案：C
18，在以太坊，geth命令，--networkid用于指定网络ID，1代表哪个网络ID？
A，主网
B，ropsten网
C，rinkeby网
D,私有网络
答案：A
A, Kadelima
B, Whithper
C, Swarm
D,ghost
Answer: B
17, in Etheria, which of the following is the centralized storage platform?
A, Kadelima
B, Whisper
C, Swarm
D, ghost
, answer: C
18, in Ethau, >Geth command --networkid is used to designate network ID, which network ID?
A, main network
B, ropstennet
C, rinkebynet
D, private network
A, BitSwap
B,BitTorrent
C,TCP
D,P2P
答案：A
20，Merkle DAGs 为IPFS提供了许多有用的属性，不包括一下那个？
A,内容寻址
B,防篡改
C,去冗余
D,去中心
答案：D
A, BitSwap
B, BitTorrent
C, TCP
D, P2P
answers: A
20, Merkle DAGs provides many useful attributes for IPFS, not just the one?
1,以下哪种不是以太坊智能合约函数和状态变量的可见性？
A,external
B,public
C,internal
D,protected
答案：D
2,
1, which of the following is not visible by the Taiyo Smart Contract function and status variable?
A, external
B, public
C, international
D, protected
answer: D
2,
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